252 TECHNICAL INFORMATION Cross Section A e I Z=I/e bh h 2 bh3 12 bh2 6 h2 h 2 h4 12 h3 6 h2 h 2 2 h4 12 2 0.1179h3 = h3 12 bh 2 2 h 3 bh3 36 bh2 24 h (2b+b1) 2 1 3b+2b1 × h 3 2b+b1 6b2+6bb1+b12 h3 36(2b+b1) 6b2+6bb1+b12 h2 12(3b+2b1) 3 3 r2 2 =2.598r2 3 r=0.886r 4 5 3 r4=0.5413r4 16 5 r3 8 r 5 3 r3=0.5413r3 16 2.828r2 0.924r2 1+2 2 r4 6 =0.6381r4 0.6906r3 0.8284a2 a b= 1+ 2 =0.4142a 0.0547a4 0.1095a3 πd2 πr2= 4 d 2 πd4 πr4 = 64 4 =0.0491d4 ≈0.05d4 =0.7854r4 πd3 πr3 = 32 4 =0.0982d3 ≈0.1d3 =0.7854r3 π r2 1− 4 =0.2146r2 e1 =0.2234r e2 =0.7766r 0.0075r4 0.0075r4 e2 =0.00966r3 ≈0.01r3 Cross Section A e I Z=I/e πab a π ba3=0.7854 ba3 4 π ba2=0.7854 ba2 4 π r2 2 e1 =0.4244r e2 =0.5756r π 8 − r4 8 9π =0.1098r4 Z1=0.2587r3 Z2=0.1908r3 π r2 4 e1 =0.4244r e2 =0.5756r 0.055r4 Z1=0.1296r3 Z2=0.0956r3 b(H−h) H 2 b (H3−h3) 12 b (H3-h3) 6H A2-a2 A 2 A4−a4 12 1 A4−a4 6 A A2−a2 A 2 2 A4−a4 12 A4−a4 2 12A 0.1179(A4−a4) = A π (d22−d12) 4 d2 2 π (d2 4−d14) 64 π = (R4−r4) 4 π d24−d14 32 d2 π R4−r4 = × 4 R πd2 a2− 4 a 2 1 3π a4− d4 12 16 1 3π a4− d4 6a 16 2b(h−d) π + d2 4 h 2 1 3π d4 12 16 +b(h3−d3) +b3(h−d) 1 3π d4 6h 16 +b(h3−d3) +b3(h−d) 2b(h−d)+ π (d12−d 2 ) 4 h 2 1 3π (d14-d 4 ) 12 16 +b(h3−d13) +b3(h−d1) 1 3π (d14−d 4 ) 6h 16 +b(h3−d13) +b3(h−d1) A: Sectional area e: Distance of Center of Gravity I: Geometrical Moment of Inertia Z=I/e: Cross Section Coefficient ( ) ( ) ( ) ( ) ( ) { } { } { } { } e b h e h h e h h b h e b h b b1 2 e 2 1b r e e r r e 2 2 b b 2 2 b e b a r e d 2e r e1 90° r b a 1 2 2r r e e 1 2 e e r r H h e b a A A e e a A A d d R e r 1 2 e a a d b e h d h e b d d 1 GeneralTechnical Information Calculation of Area, Center of Gravity and Geometrical Moment of Inertia
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